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180. Consecutive Numbers
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180.sql
MySQL
/* Write your T-SQL query statement below */
WITH
LogsNeighbors AS (
SELECT
*,
LAG(num) OVER(ORDER BY id) AS prev_num,
LEAD(num) OVER(ORDER BY id) AS next_num
FROM LOGS
)
SELECT DISTINCT num AS ConsecutiveNums
FROM LogsNeighbors
WHERE
num = prev_num
AND num = next_num;Advertisement
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